1792 United States presidential election in New Hampshire![](//upload.wikimedia.org/wikipedia/commons/thumb/2/28/Flag_of_New_Hampshire.svg/50px-Flag_of_New_Hampshire.svg.png)
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| November 2 – December 5, 1792 | 1796 → |
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| | | Nominee | George Washington | | | Party | Independent | | Home state | Virginia | | Electoral vote | 6 | | Popular vote | 2,762 | | Percentage | 100.00% | | |
President before election George Washington Independent | Elected President George Washington Independent | |
The 1792 United States presidential election in New Hampshire took place between November 2 to December 5, 1792, as part of the 1792 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for incumbent George Washington without any competitor.
Results
1792 United States presidential election in New Hampshire[1] |
Party | Candidate | Votes | Percentage | Electoral votes |
| Independent | George Washington | 2,762 | 100.00% | 6 |
Totals | 2,762 | 100.00% | 6 |
See also
References
- ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788-1860: The Official Results by County and State. Jefferson: McFarland & Company. ISBN 9780786410170.
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General articles | |
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Local results | |
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Other 1792 elections | |
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